Question

evaluate
(2/11×22/15)+(-1/6×3/4)+(-1/21×-3/5)

Answer 1

Hello dear

$( \frac{2}{11} \times \frac{22}{15} ) + ( \frac{ - 1}{6} \times \frac{3}{4} ) + ( \frac{ - 1}{21} \times \frac{ - 3}{5} ) \\ \\ = \frac{4}{15} + \frac{ - 1}{8} + \frac{ - 1}{35} \\ \\ = \frac{224 - 105 + 24}{840} \\ \\ = \frac{143}{840}$


Hope it helps.

Answer 2

Concept:

Simplification using BODMAS.

BODMAS is a rule which tells us the order of mathematical operations.

In BODMAS,

B stands for Brackets

O stands for Of

D stands for Division

M stands for Multiplication

A stands for Addition

S stands for Subtraction

The order of these operations is also the same as they are written.

Given:

(2/11×22/15)+(-1/6×3/4)+(-1/21×-3/5)

Answer:

(2/11×22/15)+(-1/6×3/4)+(-1/21×-3/5) = 143/840

Solution:

= (2/11×22/15)+(-1/6×3/4)+(-1/21×-3/5)

= $(\frac{2}{11} \times \frac{22}{15} ) + (-\frac{1}{6} \times \frac{3}{4} ) + (-\frac{1}{21} \times - \frac{3}{5})$

First of all, according to BODMAS, we will solve brackets.

=  $(\frac{2}{1} \times \frac{2}{15} ) + (-\frac{1}{2} \times \frac{1}{4} ) + (-\frac{1}{7} \times - \frac{1}{5})$

= $(\frac{4}{15} ) + (-\frac{1}{8}) + (\frac{1}{35} )$

= $\frac{4}{15} -\frac{1}{8} + \frac{1}{35}$

Now, we will do addition.

= $\frac{4}{15} + \frac{1}{35} -\frac{1}{8}$

LCM of 15 and 35 is 105.

$= \frac{7(4) + 1(3)}{105} - \frac{1}{8}$

= $\frac{28 + 3}{105} - \frac{1}{8}$

= $\frac{31}{105} - \frac{1}{8}$

Now we will do subtraction.

LCM of 105 and 8 is 840.

= $\frac{31(8) - 1(105)}{840}$

= $\frac{248 - 105}{840}$

= $\frac{143}{840}$

Hence, the answer is  $\frac{143}{840}$.

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