evaluate 2 × 2^1/2 + 2^3/2
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Answer:
Let the first odd number = x
Second odd number = x+2
And the third odd number = x+4
According to the condition,
x+x+2+x+4=63
\Rightarrow3x+6=63
⇒3x=63-6
⇒3x=57
⇒x=\frac{57}{3}
⇒x=19
∴ First odd number = x = 19
Second odd number = x + 2 = 19 + 2 = 21
third odd number = x + 4 = 19 + 4 = 23
Hence, the three consecutive odd numbers are 19, 21 and 23.
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The answer is 6. Thank you. Please make it the brainiest answer
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