Question

evaluate (2^2)^3 +(1/3)^0 + (3^2)^3 ×{(1/3)^-1}^-3​

Answer 1

Step-by-step explanation:

${( {2}^{2} )}^{3} + ( \frac{1}{3})^{0} + ({ {3}^{2} })^{3} \times ({\frac{1}{3} }^{ - 1} ) ^{ - 3} \\ = {( {4} )}^{3} + ({ {9} })^{3} \times ({\frac{3}{1} }) ^{ - 3} \\ = {64} + 729 \times { \frac{1}{3} }^{3} \\ = 793 \times \frac{1}{27} \\ = \frac{793}{27}$

Answer 2

Answer:

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Step-by-step explanation:

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