Question

evaluate (2⁰+3^-1)×3²​

Answer 1

Answer:

2^2×2^-5

32×1/32

ans=0

Answer 2

$(2⁰+3^{-1})×3²$

$=(1+3^{−1}) \times {3}^{2}$

$= (1 + \frac{1}{3} ) \times {3}^{2}$

$= \frac{4}{3} \times {3}^{2}$

$= \frac{4}{3} \times 9$

$= 12$