Question

evaluate (2/3)^2×(2/5)^-3×(3/5)^2

Answer 1

Hi Your Answer is :-
(2/3)²×(2/5)^-3×(3/5)²
=4/9×(5/2)³×9/25
=4/9×125/8×9/25
=5/2 (Answer)

Answer 2

Given,

• $(2/3)^2*(2/5)^{-3} *(3/5)^2$ is given.

To find,

• We have to evaluate the given expression.

Solution,

We can simply evaluate the given expressions by using the laws of exponents.

         = $(2/3)^2*(2/5)^{-3} *(3/5)^2$

As we know $a^{-m} = 1/a^m$, then

        =  $(2/3)^2*(5/2)^3} *(3/5)^2$

Expanding the above expression, we get

         =  $(4/9) * (125/8) * (9/25)$

        =  5/2

Hence, $(2/3)^2*(2/5)^{-3} *(3/5)^2$ can be evaluated as 5/2.