Math, asked by murugeshhiremath, 11 months ago

evaluate (√2+√3)2+(√5+√2)2​

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Answered by vatsal00
9

{\underline{\underline{Answer~:}}}

 =  {( \sqrt{2}  +  \sqrt{3}) }^{2}  +  {( \sqrt{5} +  \sqrt{2}  )}^{2}  \\  \\  = 2 + 3 + 5 + 2 \\  \\  = 12

\color{Red}{Answer~is~12}

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Answered by LilyWhite
5

( √2+√3 )2 + ( √5+√2 )2

(2 + 3 ) + ( 5 + 2 )

5 + 7

12

or

( √2+√3)2 + ( √5+√2)

【 (√2)2 + (√3)2 + 2 . √2 . √3 】 +

【 (√5)2 + (√2)2 + 2 . √5 . √2 】

【 2 + 3 + 2 √6 】 + 【 5 + 2 + 2 √10 】

【 5 + 2√6 】 + 【 7 + 2√10 】 = 0

【 5 + 2√6 】 = 【 7 + 2√10 】

【 5 + 7 】 = 【 2√6 + 2√10 】

【 12 】 = 【 4√60 】

12 / 4 = 60

3 = 60

20

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