Math, asked by 15vsa010384, 6 months ago

evaluate[(2/3)power of 2 ] power of -2+[(3/2) power of 2]power of 0​

Answers

Answered by preeti9578
1

Step-by-step explanation:

[(2/3)² ]^-² + [(3/2)²]^0

(2/3)^²×-² + (3/2)²×^0

(2/3)^-⁴ + (3/2)^0

(3/2)⁴ + 1

81 + 1

16

81+16

16

97

16

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