Math, asked by aayaanali1010, 6 months ago

evaluate (2/3) to the power minus 2 ×(3/2) to the power 3​

Answers

Answered by shrivastavanaimish
4

Answer:

Step-by-step explanation:

(2/3)^-2×(3/2)^3

(3/2)^2×(3/2)^3

Now the base is same so we add the powers

(3/2)^2+3

(3/2)^5=243/32

Answered by Anonymous
4

Step-by-step explanation:

 (\frac{2}{3} )^{ - 2}  \times ( \frac{3}{2} )^{3}

( \frac{a}{b} )^{ - m }  = ( \frac{b}{a} )^{m}

( \frac{2}{3} )^{ - 2}  =(  \frac{3}{2})^{2}

( \frac{a}{b} )^{m}  =  \frac{ {a}^{m} }{ {b}^{m} }

( \frac{3}{2} ) ^{2}  \times ( \frac{3}{2} )^{3}

 \frac{ {3}^{2} }{ {2}^{2} }  \times  \frac{ {3}^{3} }{ {2}^{3} }

 \frac{9}{4}  \times   \frac{27}{8}

 \frac{243}{32}

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