Question

evaluate 2^30+2^29-2 solved the problem ​

Answer 1

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we can simplify as follows

229(21−1)2229(21−1)2. From this we do have 22922292

At this point put 22922292 = 228228. Cross multiply 229=228∗2229=228∗2

At the end, we do have 229=229229=229

The answer is C.

Answer 2

Step-by-step explanation:

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