Question

evaluate (2+3i).(3-2i)​

Answer 1

Answer:

12 +5i

Step-by-step explanation:

(2+3i)(3-2i)

=6-4i+9i-6i²

=6+5i+6

=12+5i

Answer 2

Answer of the above given product problem is 12 + 5i .

Given: (2+3i).(3-2i)

To find: Product of the above problem.

Solution: According to the Problem

let, a = (2+3i)

and b = (3-2i)

so, to find product of a and b  [a.b]

opening the bracket => 2 .(3-2i) + 3i .(3-2i)

=> 2*3 = 6 , 2*-2i = -4i ; 3i * 3 = 9i , 3i * -2i = -6$i^{2}$

Now, since $i^{2}$ = -1

therefore, this implies

=> a.b = 6+ (-4i) + 9i + (-6$i^{2}$)

=> a.b = 6 - 4i + 9i  + (-6* -1)

=> a.b = 6 - 4i + 9i + (+6)

=> a.b = 6 - 4i + 9i + 6

=> a.b = 12 + 5i