Math, asked by rekharajwar918, 5 months ago

evaluate (2/3x-3/2x-1)^2​

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Answered by Enrique001
1

Answer:

 {  (\frac{2x}{3}  -  \frac{3}{2x}  - 1)}^{2}

 = { \frac{2x \times 2x - 3 \times 3 - 3 \times 2x}{3 \times 2x} }^{2}

= [(4x^2-6x-9)/6x]^2

Answered by lakshyaagarwalpkt
0

THERE IS THE ANSWER TO YOUR EQUATION USING EXPANSIONS. HOPE THIS HELPS YOuTHANK YOU FOR THE POINTS, LAKSHYA AGARWAL .

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