evaluate (2.7)3 - (1.7)3 - (1.1)3 using a suitable identity
tiasaghosh5876:
(2.7) *3 or its cube ?
Answers
Answered by
25
Hey !
Its simple ...
(2.7)³ - (1.7)³ - (1.1)³
(27/10)³ - (17/10)³ - (11/10)³
[27/10 - 17/10 - 11/10 ]³
[ 1.1 ]³
1.331
Its simple ...
(2.7)³ - (1.7)³ - (1.1)³
(27/10)³ - (17/10)³ - (11/10)³
[27/10 - 17/10 - 11/10 ]³
[ 1.1 ]³
1.331
Answered by
9
Answer:
(2.7)^3-(1.7)^3-(1.1)^3
(27/10)^3-(17/10)^3-(11/10)^3
(27/10-17/10-11/10)^3
(27/10-28/10)^3
(-1/10)^3
(-0.1)^3
-0.001
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