Math, asked by purtyakriti, 3 months ago

evaluate 2(cos^245° +tan^260°)-6(sin^245°-tan^230°)

Answers

Answered by antonyharoldcj
0

Answer:

don't know the correct answer

Answered by lilicutie47
1

Step-by-step explanation:

2(cos²45+tan²60°)-6(sin²45°-tan²30°)

the next step on the clip

=2×7/2-6×1/6 =7-1=6

thus, 2(cos²45+tan²60°)-6(sin²45°-tan²30°)

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