Math, asked by avinashmahtodx001, 9 months ago

Evaluate 2 cos 60° + 3 sin 45° -3 sin 30° + 2 cos 90%

Answers

Answered by cdnjs
1

Answer:

\frac{3\sqrt{2} - 1}{2}

Step-by-step explanation:

we know value of cos60° = \frac{1}{2} , sin45° = \frac{1}{\sqrt{2} } , sin30° = \frac{1}{2} and cos90° = 0

so we have:

= 2 cos 60° + 3 sin 45° -3 sin 30° + 2 cos 90°

= 2*(1/2) + 3*(\frac{1}{\sqrt{2} }) - 3*(1/2) +2*0

= 1 + 3/(\sqrt{2}) - 3/2

= \frac{3\sqrt{2} - 1}{2}

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