Math, asked by rohitbagoriya1977, 1 year ago

evaluate 2(cos sqare45+tan sqare60)-6(sin sqare45-tan sqare30

Answers

Answered by khushijain973
1
2 (1/root 2)square - 6 ( 1 / root 2 )square - 1/ root 3 square .
1- 3 - 1/3
-2-1/3=-7/3
Answered by neerajvermag11
0

Given :-

2(cos²45° +tan²60°)-6(sin²45°- tan²30°)

= 2[(1/√2)²+(√3)²]-6[(1/√2)²-(1/√3)²]

= 2(1/2+3) - 6(1/2-1/3)

= 2(1+6/2)-6(1/6)

= 7-1=6

Hope helps u

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neerajvermag11: Thnx
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