Evaluate : 2 log 8+ log36-log 1.5-3 log2
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Answer:
6 - log 3
Step-by-step explanation:
I assume the base of logarithm is 2, then
2log2³ = 6log2 = 6
log 36 = log(4×9) = 2log2 + 2log3 = 2 + 2log3
log1.5 = log(3÷2) = log3 - log2 = log3 - 1
3log2 = 3
6 + 2 + 2log3 - log3 + 1 - 3 = 6 - log3
In general (for another bases), 6log 2 - log 3
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Answer:
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