Question

evaluate 2 power minus 3 root 6 into 3 power 2 divide by 6 power 3 into 2 power 5
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Answer 1

Answer:

==>  ${(2^{-12})(3^{-2})$

Step-by-step explanation:

$\frac{(2^{-3}\sqrt{6}) (3^{2}) }{(6^{2}) (2^{5} ) }$

==> $\frac{(2^{-3}((2^{-2})(3^{-2}) )) (3^{2}) }{((2^{2})(3^{2}) ) (2^{5} ) }$

==> $\frac{(2^{-3-2}) (3^{2-2}) }{(3^{2})(2^{5+2} ) }$

==>$\frac{(2^{-5}) (3^{ 0}) }{(3^{2})(2^{7} ) }$

==> ${(2^{-5-7})(3^{-2})$

==> ${(2^{-12})(3^{-2})$