Question

evaluate 2 sin square 30 - 3 cos square 30 + tan 60 + 3 sin square 90 ​

Answer 1

2Sin²30° - 3Cos²30° + tan 60° + 3Sin²90°

On putting all the trigonometric values in this equation , we get:

2 x (1/2)² - 3 x (√3/2)² + √3 + 3 x (1)²

=} 2 x 1/4 - 3 x 3/4 + √3 + 3 x 1

=} 1/2 - 9/4 + √3 + 3

=} (2 - 9 + 4√3 + 12)/4

=} (5+4√3)4

Answer 2

Simplify:

Step-by-step explanation:

$\ Given \ value:\\\\2\sin^2 30 -3\cos^230+ \tan 60 + 3\sin^290\\\\\ Solution:\\\\\therefore \sin 30 = \frac{1}{2}\\\\\cos 30 = \frac{\sqrt{3}}{2}\\\\ \tan 60 = \sqrt{3} \\\\\sin 90 = 1\\\\\rightarrow 2(\frac{1}{2})^2 -3(\frac{\sqrt{3}}{2})^2+ (\sqrt{3}) + 3(1)^2 \\\\\rightarrow 2(\frac{1}{4}) -3(\frac{3}{4})+ (\sqrt{3}) + 3 \\\\\rightarrow (\frac{1}{2}) -(\frac{9}{4})+ (\sqrt{3}) + 3 \\\\\rightarrow \frac{(2-9+4\sqrt{3}+12)}{4} \\\\\rightarrow \frac{(5+4\sqrt{3})}{4}$

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