Math, asked by mukthak22, 1 year ago

evaluate 2 tan^2 45°+cos^2 30°-sin^2 60°

Answers

Answered by Shalmali040203
191

Answer: answer is 2


Step-by-step explanation:


Attachments:
Answered by SerenaBochenek
145

Answer:

The value of given expression is 2.

Step-by-step explanation:

we have to evaluate

2\tan^2 45^{\circ}+\cos^2 30^{\circ}-\sin^2 60^{\circ}

\tan 45^{\circ}=1

\cos 30^{\circ}=\frac{\sqrt3}{2}

\sin 60^{\circ}=\frac{\sqrt3}{2}

2\tan^2 45^{\circ}+\cos^2 30^{\circ}-\sin^2 60^{\circ}

2(1)^2+(\frac{\sqrt3}{2})^2-(\frac{\sqrt3}{2})^2

2+\frac{3}{4}-\frac{3}{4}

2

The value of given expression is 2.

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