Question

evaluate (2-y)³ and expand: i) ( 3a-4b-3c)²​

Answer 1

Answer:

(2 - y)³ = 8 + y³ - 12y  - 6y²

(3a - 4b - 3c)² = 9a² + 16b² + 9c² - 18ac - 24bc + 24ab

Step-by-step explanation:

(2 - y)³

= 2³ + y³ - 3(2)²(y) - 3(2)(y)²

 = 8 + y³ - 12y  - 6y²

(3a - 4b - 3c)²

= (3a)² + (4b)² + (3c)² - 2(3a)(3c) - 2(4b)(3c) + 2(3c)(4b)

= 9a² + 16b² + 9c² - 18ac - 24bc + 24ab