Question

Evaluate: 25−12 ÷6 −3×8 formula​

Answer 1

Answer:

BODMAS rule mark me brainliest

Answer 2

Answer:

Required value is (-1)

Step-by-step explanation:

Given,25-12÷6 −3×8

By BODMAS rule,we can solve this problem.

By BODMAS rule,

Bracket - Of - Division - Multiplication - Addition - Subtraction

So,

$25 - 12 \div 6 - 3 \times 8 \\ = 25 - 2 - 3 \times 8 \\ = 25 - 2 - 24 \\ = 25 - 26 \\ = - 1$

Required value of the given term is (-1).

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

#SPJ2