Math, asked by kirankumar367, 8 months ago

Evaluate (-256)×(-41)+(-256)×31-256×20 using distributive

Answers

Answered by ahanatarafder06
1

Answer:

(-256)×(-41)+(-256)×31-256×20 \\  = ( - 256) \times ( - 41 + 31 + 20) [<strong>Usi</strong><strong>ng</strong><strong> </strong><strong>\</strong><strong>\</strong><strong> </strong><strong>distributive\</strong><strong>:</strong><strong> </strong><strong>property</strong><strong>]</strong> \\  = ( - 256) \times 10 \\  =  - 2560

Answered by daksh6397
1

Step-by-step explanation:

−256)×(−41)+(−256)×31−256×20=(−256)×(−41+31+20)[Usingdistributiveproperty]=(−256)×10=−2560

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