Math, asked by bhavananagesh01, 1 month ago

evaluate
27^-1/3 - 343^-1/3

Answers

Answered by llDPllForever
1

Answer❣

Given

We have given two points M( -5,-2) and N( 3,2)

To find

we have to find the point on x - axis which is equidistant from the points M and N

Solution,

since ,we don't know the points let us assume the point on x axis be ( x,0)

Note : On x-axis the y will be zero and on Y-axis x will be zero.

let x be 'a'

so , our new point be P (a,0)

According to the questio:

If the point P is equidistant from M and N

then their distance between the points PM and PN must be equal.

Now, by using distance formula we will find distance between the two points.

Distance Between P and M

Distance formula

D=√(x₂- x₁)²+(y₂- y₁)²

M( -5,-2) and P(a,0)

x₁= -5 ;x₂ = a ; y₁= -2 & y₂ = 0

PM= √ (a+5)²+(0+2)²

identity :(a+b)²= a²+b²+2ab

PM= √ a²+5²+2(a)(5)+2²

PM= √a²+25+10a+4=√ a²+10a+29

Distance between P and N

P(a,0) N ( 3,2)

PN=√ (3-a)²+(2-0)²

PN= √ 9+a²-6a+4= √ a²-6a+13

Now , comparing both PM and PN

√ a²+10a+29=√a²-6a+13

Squaring both sides

PM²= PN²

(√a²+10a+29)²= (√a²-6a+13)²

a²+10a+29=a²-6a+13

a² gets cancelled as base same

=> 10a +29= -6a+13

=> 10a+6a=13-29

=> 16a = -16

=>a = -1

Thus,the point is (a,0) = (-1,0)

Therefore, (-1,0) is the point on the x-axis which is equidistant from the points M

Answered by sonumondithoka
1

Step-by-step explanation:

STEP

1

:

27

Simplify ———

343

Equation at the end of step

1

:

(27

(———)1) ÷ 3

343

STEP

2

:

2.1 27 = 33

(27)1 = (33)1 = 33 2.2 343 = 73 (343)1 = (73)1 = 73

Equation at the end of step

2

:

33

—— ÷ 3

73

STEP

3

:

33

Divide —— by 3

73

Dividing exponents:

3.1 33 divided by 31 = 3(3 - 1) = 32

Final result :

9

——— = 0.02624

343

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