Question

evaluate:27⅓+9³/² -3(5)-(1/81)-½​

Answer 1

Evaluate :

${ \: \: \: \: \implies\sf {27}^{ \frac{1}{3} } + {9}^{ \frac{3}{2} } -3(5)-(1/81)^{ \frac{ - 1}{2} } }$

Step by step Explanation:

$\\{ \: \: \: \: \implies\sf {27}^{ \frac{1}{3} } + {9}^{ \frac{3}{2} } -3(5)-(1/81)^{ \frac{ - 1}{2} } }$

${ \: \: \: \: \implies\sf \sqrt[3]{27} + { {3} }^{ 2 \times \frac{3}{2} } -15- \sqrt{81} }$

${ \: \: \: \: \implies\sf \sqrt[3]{ {3}^{3} } + { {3} }^{ 3 } -15- \sqrt{ {9}^{2} } }$

${ \: \: \: \: \implies\sf 3 + 27 -15- 9 }$

${ \: \: \: \: \implies\sf 30 -24 }$

${ \: \: \: \: \implies\sf 6 }$

$\\{ \: \boxed{ \: \: \sf {27}^{ \frac{1}{3} } + {9}^{ \frac{3}{2} } -3(5)-(1/81)^{ \frac{ - 1}{2} } = \bf6 }}$

${\footnotesize\begin{gathered}\begin{gathered}\\\\\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \bigstar \: \underline{\bf{}}\\ {\boxed{\begin{array}{c | c} \frac{ \: ~~~~~~~~~~\: \: \: \: \:\sf \pink{Laws} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }{ } &\frac{ \: ~~~~~~~~~~ \: \: \: \: \:\sf \green{Example } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }{ }\\\sf \bigstar{a}^{m} \times {a}^{n} = {a}^{m + n} & \sf {a}^{2} \times {a}^{3} = {a}^{2 + 3} = {a}^{6} \\ \\ \sf \bigstar{a}^{m} \div {a}^{n} = {a}^{m - n}& \sf {a}^{3} \div {a}^{2} = {a}^{3 - 2} = {a}^{1} \\ \\ \sf{\bigstar \: \: \: \: \: \: ( {a}^{m} ) ^{n} = {a}^{mn} } & \sf( {a}^{2} ) ^{3} = {a}^{2 \times 3} = {a}^{6} \\ \\ {\bigstar\sf a {}^{m} \times {n}^{m} = (ab) ^{m} } &\sf a {}^{2} \times {b}^{2} = (ab) ^{2}\\ \\ \sf\bigstar \: \: \: \: \: {a}^{0} = 1& \sf {2}^{0} = 1 \: \: \: \: \\ \\ \sf \bigstar \: \: \: \: {\dfrac{ {a}^{m} }{ {b}^{m} }= \left( \dfrac{a}{b} \right) ^{m} }& \sf{\dfrac{ {a}^{2} }{ {b}^{2} }= \left( \dfrac{a}{b} \right) ^{2} }\\\\\bigstar~~~~~~~ \sf x^{\frac{m}{n} }=\sqrt[n]{x^m}\sf = (\sqrt[n]{x})^m & \sf x^{\frac{2}{3} }=\sqrt[3]{x^2} = (\sqrt[n]{x})^m\\ \\\\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}}$

Answer 2

Answer:

Refer to the attachment photo.

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