Math, asked by pranav1562005, 11 months ago

Evaluate 27y^2 + 125z^3 by using suitable identity.​

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Answers

Answered by zahaansajid
3

27y³ + 125z³ = (3y+5z)(9y² - (3y×5z) + 25z²)

= (3y + 5z)(9y² - 15yz + 25z²)

I used the identity a³+ = (a+b)(a²-ab+)

Hope this is helpful to you

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Answered by CharmingPrince
16

Answer :

Step by step explanation :-

\rightarrow27{y}^{3} + 125{z}^{3}

  • Write in expontential form.

\rightarrow{3}^{3} {y}^{3} + {5}^{3} {z}^{3}

  • Calculate the products.

\rightarrow({3y})^{3} + ({5z})^{3}

  • Factor the obtained expression.
  • Identity using :- {a}^{3} + {b}^{3} = (a + b)({a}^{2} - ab + {b}^{2}

\rightarrow(3y + 5z)(({3y})^{2} - 3y × 5z + ({5z})^{2})

\rightarrow(3y + 5z)(9{y}^{2} - 15yz + 25{z}^{2})

Thank you !!

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