Math, asked by bk7112667, 1 month ago

evaluate : (2a + 3b + 4c) power 2 + (2a - 3b + 4c) power 2 + (2a + 3b - 4c) power 2​

Answers

Answered by Timothykk
1

Answer:

=12a^2 + 9b^2 + 16c^2

Step-by-step explanation:

((2a)^2 + (3b)^2 + (4c)^2 )) + ((2a)^2 - (3b)^2 +(4c)^2 ))

+ ((2a)^2 + (3b)^2 - (4c)^2 ))

= 4a^2 + 9b^2 + 16c^2

+

4a^2 - 9b^2 + 16c^2

+

4a^2 + 9b^2 - 16c^2

like terms:

=4a^2 + 4a^2 + 4a^2 + 9b^2 - 9b^2 + 9b^2 + 16c^2 + 16c^2 - 16c^2

=12a^2 + 9b^2 + 16c^2

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