Question

Evaluate [2cos43°cosec47°/5(cos^2 29°+cos^2 61°)] - 3tan^2 60° - cos(35°-theta) + sin(55°+theta)

Answer 1

Answer:

Step-by-step explanation:

[2 cos 43 cosec 47/5( cos ^2 29+ cos^2 61)]- 3 tan^2 60- cos (35-theta)+ sin (55+ theta)

[2cos43 cosec (90-43)/5(cos^2 29+ cos^2 ( 90-29)]- 3 tan^2 60- cos( 35 - theta + sin (90-55-theta)

2 cos43 sec43/5( cos^2 29+ sin^2 29) - 3 ×3- cos(35 + theta) + cos( 35- theta)

2/5-9

2-45/5

-43/5