Math, asked by diya814613, 8 months ago

Evaluate 2cos45° sin15°​

Answers

Answered by Truptipratikhya
1

Answer:

2 cos 45°(sin15°)

=:2×1/√2{sin(60-45)}

=:√2{sin60°.cos45°-cos 60°.sin45°}

=:√2(√3/2.1/√2-1/2.1/√2)

=:√2(√3/2√2-1/2√2)

=:√2×√3-1/2√2

=:√3-1/2

Similar questions