Evaluate 2cos45° sin15°
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Answer:
2 cos 45°(sin15°)
=:2×1/√2{sin(60-45)}
=:√2{sin60°.cos45°-cos 60°.sin45°}
=:√2(√3/2.1/√2-1/2.1/√2)
=:√2(√3/2√2-1/2√2)
=:√2×√3-1/2√2
=:√3-1/2
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