Math, asked by siddiqamamun, 1 year ago

evaluate: 2sin30^2cot30-3cos60^2sec30^2

Answers

Answered by thameshwarp9oqwi
0

Answer:

2 SIN²30·COT 30 - 3 COS²60 .  SEC²30

==> 2(1/2)².(√3) - 3(1/2)² . (2/√3)²

==> 2/4 . √3 - 3/4 . 4/3

==> 2√3/4 - 12/12

==> 2√3/4  - 0

==> √3/2


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