Question

evaluate 2tansq45°+cossq30°-sinsq60°​

Answer 1

We know that,

Tan45° = 1

$cos30°= \frac{ \sqrt{3} }{2} \\ \\ \\ \\ sin60°= \frac{ \sqrt{3} }{2}$

$2 {tan}^{2} 45°+cos ^{2} 30 - \sin^{2} 60 \\ \\ = > 2 ({1})^{2} + ({ \frac{ \sqrt{3} }{2} })^{2} - \: ({ \frac{ \sqrt{3} }{2} })^{2} \\ = > 2 + \frac{3}{4} - \frac{3}{4} \\ = > 2$