Question

Evaluate 2to the power x +2to the power x-1 /2to the power x+1-2​

Answer 1

Step-by-step explanation:

$= ({ { ({2}^{x + 2} )}^{x - \frac{1}{2} } )}^{x + 1 - 2} \\ = ({ { ({2}^{x + 2} )}^{ \frac{2x - 1}{2} } )}^{x - 1} \\ = ({ { {2}^{(x + 2)} }^{ \times \frac{(2x - 1)}{2} } )}^{x - 1} \\ = { ({2}^{ \frac{2 {x}^{2} - x + 4x - 2 }{2} } )}^{x - 1} \\ = { ({2}^{ \frac{(2 {x}^{2} + 3x - 2) }{2} \times (x - 1)} )}^{} \\ = {2}^{ \frac{ {2x}^{3} + 3 {x}^{2} - 2x - 2 {x}^{2} - 3x + 2}{2} } \\ = {2}^{ \frac{ {2x}^{3} + {x}^{2} - 5 x + 2}{2} }$

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