Math, asked by roshuverma18, 1 month ago

evaluate (2x-1/2x)² ​

Answers

Answered by ayushkhairnar3213
0

Answer:

Step-by-step explanation:

Multiply the numbers

(

2

1

1

2

)

2

(2x{\color{#c92786}{-1}} \cdot {\color{#c92786}{\frac{1}{2}}}x)^{2}

(2x−1⋅21​x)2

(

2

1

2

)

2

(2x{\color{#c92786}{-\frac{1}{2}}}x)^{2}

(2x−21​x)2

2

Combine multiplied terms into a single fraction

(

2

1

2

)

2

(2x-\frac{1}{2}x)^{2}

(2x−21​x)2

(

2

+

2

)

2

(2x+\frac{-x}{2})^{2}

(2x+2−x​)2

3

Find common denominator

(

2

+

2

)

2

(2x+\frac{-x}{2})^{2}

(2x+2−x​)2

(

2

2

2

+

2

)

2

(\frac{2 \cdot 2x}{2}+\frac{-x}{2})^{2}

(22⋅2x​+2−x​)2

4

Combine fractions with common denominator

(

2

2

2

+

2

)

2

(\frac{2 \cdot 2x}{2}+\frac{-x}{2})^{2}

(22⋅2x​+2−x​)2

(

2

2

2

)

2

(\frac{2 \cdot 2x-x}{2})^{2}

(22⋅2x−x​)2

5

Multiply the numbers

(

2

2

2

)

2

(\frac{{\color{#c92786}{2}} \cdot {\color{#c92786}{2}}x-x}{2})^{2}

(22⋅2x−x​)2

(

4

2

)

2

(\frac{{\color{#c92786}{4}}x-x}{2})^{2}

(24x−x​)2

6

Combine like terms

(

4

2

)

2

(\frac{{\color{#c92786}{4x}}{\color{#c92786}{-x}}}{2})^{2}

(24x−x​)2

(

3

2

)

2

(\frac{{\color{#c92786}{3x}}}{2})^{2}

(23x​)2

Show less

Solution

(

3

2

)

Answered by poonam847211devi
2

Answer:

(2x-1/2x)²= (2x)²+(1/2x)²-2×2x×1/2x

= 4x²+1/4x²-2

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