Math, asked by pothanvarma10, 2 days ago

evaluate (2x+1) (x+2)(2x-1) ​

Answers

Answered by abhaykakkattil71
2

Answer:

(2x+1) (x+2) (2x-1)

= { (2x + 1) (x + 2) } (2x - 1)

= { 2x (x + 2) + 1 (x + 2) } (2x - 1)

= { 2x² + 4x + x + 2 } (2x - 1)

= 2x - 1 ( 2x² + 5x + 2 )

= 2x ( 2x² + 5x + 2 ) - 1 ( 2x² + 5x + 2 )

= 4x³ + 10x² + 4x - 2x² - 5x - 2

= 4x³ + 8x² - x - 2

Hope my answer is correct..

Thank u..

Answered by rajenderaprasad1970
1

Answer:

4x^3 + 8x^2 - X - 2

Step-by-step explanation:

4x^3+2x^2+8x^2-4x+2x^2

-x + 4x^3 - 2

=4x^3+8^2-x-2Ans

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