Question

evaluate (2x^2+3x-7)*(3x^2-5x+4)​

Answer 1

Answer:

$\bf{ \boxed{ \bold{6x^4-x^3-28x^{2} +47x-28}}}$

Step-by-step explanation:

(2x²+3x−7)(3x²−5x+4)

→ (2x²)(3x²)+(2x²)(−5x)+(2x²)(4)+(3x)(3x²)+(3x)(−5x)+(3x)(4)+(−7)(3x²)+(−7)(−5x)+(−7)(4)

→ 6x⁴−10x³+8x²+9x³−15x²+12x−21x²+35x−28

→ 6x⁴−x³−28x²+47x−28

You need to know that :-

• Polynomials : Polynomial are variable based dialect in the language of maths.

• In a common language , polynomials are defined as a string of variables and numbers put together.

• Highest power of a polynomial is called degree of polynomial.

• A constant polynomial is nothing but a monomial with degree zero.

• Equation: A condition or a constraint placed on x and y coordinates.

• Curve: A union of points that satisfy a particular condition.

• Remainder theorem: When p(x) is divided by (x - a) then the remainder is given by p(a).

Answer 2

Answer:

Given

evaluate (2x^2+3x-7)*(3x^2-5x+4)

To find

Evaluate

Solution

(2x²+3x−7)(3x²−5x+4)

= (2x²)(3x²)+(2x²)(−5x)+(2x²)(4)+(3x)(3x²)+(3x)(−5x)+(3x)(4)+(−7)(3x²)+(−7)(−5x)+(−7)(4)

= 6x⁴−10x³+8x²+9x³−15x²+12x−21x²+35x−28

Evaluated value 6x⁴−x³−28x²+47x−28

$\huge \fbox {Hope it helps}$