Question

Evaluate - (2x+3y)^2

Answer 1

ANSWER:-

➣

$(2x + 3y)^2$

We know:-

$\boxed{\bf{(a+b)^2 = a^2 + b^2 + 2ab}}$

here,

$a = 2x$

$b = 3y$

Therefore,

$\longrightarrow{(2x)^2 + (3y)^2 + 2(2x \times 3y)}$

$\longrightarrow{4x^2 + 9y^2 + 2(6xy)}$

$\bf{\longrightarrow{4x^2 + 9y^2 + 12xy}}$

Answer 2

$\huge{\sf{\orange{Answer}}}$

$- {(2x + 3y)}^{2}$

$- (({2x})^{2} + ({3y})^{2} + 2 \times 2x \times 3y)$

$- (4 {x}^{2} + 9 {y}^{2} + 12xy)$

Now change the signs.

$-4 {x}^{2} - 9 {y}^{2} - 12xy$

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

$Additional~Information$

Note Here I have used

.➣

${(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab$

And signs are changed on the following bases

➣ (+) (+) = +

(+) (-) = -

(-) (-) = +

(-) (+) = -