evaluate (2x-3y+3z)^2
Answers
Answered by
3
Answer:
(2x-3y+3z)^2
=(2x)^2+(-3y)^2+(3z)^2+2.2x(-3y)+2.(-3y).3z+2.3z.2x
=4x^2+9y^2+9z^2-12xy-18yz+12xz
Answered by
7
Answer :-
4x² + 9y² + 9z² - 12xy - 18yz + 12xz - 18xyz
Step-by-step explanation :-
The given expression is (2x - 3y + 3z)²
Identity used:
→ (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ac + abc
Solution:
In the given question,
- a = 2x
- b = -3y
- c = 3z
(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ac + abc
⇒ (2x - 3y + 3z)² = (2x)² + (-3y)² + (3z)² + 2(2x)(-3y) + 2(-3y)(3z) + 2(2x)(3z) + [(2x)(-3y)(3z)]
⇒ (2x - 3y + 3z)² = 4x² + 9y² + 9z² + (-12xy) + (-18yz) + 12xz + [-18xyz]
⇒ (2x - 3y + 3z)² = 4x² + 9y² + 9z² - 12xy - 18yz + 12xz - 18xyz
∴ [4x² + 9y² + 9z² - 12xy - 18yz + 12xz - 18xyz]
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