evaluate 2x+3y=8,xy=2
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Answer:
When x = 3 then y = 2/3
When x = 1 then y = 2
Step-by-step explanation:
2x+3y=8 ----(1)
xy=2
y = 2/x --(2)
put value of y in -(1)
2x + 3(2/x) = 8
2x + 6/x = 8
(2x² + 6)/x = 8
2x² + 6 = 8x
2x² - 8x + 6 = 0
x² - 4x + 3 = 0
x² - x - 3x + 3 = 0
x(x - 1) -3(x - 1) = 0
(x - 3)(x - 1) = 0
x - 3 = 0 ;x - 1 = 0
x = 3 ; x = 1
when x = 3 put value of x in eq---(1)
2(3) + 3y = 8
6 + 3y = 8
3y = 8 - 6
3y = 2
y = 2/3
When x = 1 put value of x = 1 eq----(1)
2(1) + 3y = 8
2 + 3y = 8
3y = 8 - 2
3y = 6
y = 6/3
y = 2
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