Question

evaluate 2x+3y=8,xy=2​

Answer 1

Answer:

When x = 3 then y = 2/3

When x = 1 then y = 2

Step-by-step explanation:

2x+3y=8 ----(1)

xy=2​

y = 2/x --(2)

put value of y in -(1)

2x + 3(2/x) = 8

2x + 6/x = 8

(2x² + 6)/x = 8

2x² + 6 = 8x

2x² - 8x + 6 = 0

x² - 4x + 3  = 0

x² - x - 3x + 3 = 0

x(x - 1) -3(x - 1) = 0

(x - 3)(x - 1) = 0

x - 3 = 0          ;x - 1 = 0

x = 3 ; x = 1

when x = 3 put value of x in eq---(1)

2(3) + 3y = 8

6 + 3y = 8

3y = 8 - 6

3y = 2

y = 2/3

When x = 1 put value of x = 1 eq----(1)

2(1) + 3y = 8

2 + 3y = 8

3y = 8 - 2

3y = 6

y = 6/3

y = 2