Math, asked by purvigarg034, 2 months ago

evaluate [3^-1*4^1+5^-1]^-1​

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Answers

Answered by AdiSTo
0

Step-by-step explanation:

Plz see the attachment above

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Answered by masura8080
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From the given question the correct answer is:

Hence, the answer of [3^{-1} \times 4^{-1}+5^{-1}]^{-1​} is =\frac{60}{17}

Given:

[3^{-1} \times 4^{-1}+5^{-1}]^{-1​}

To find:

[3^{-1} \times 4^{-1}+5^{-1}]^{-1​}=?

Solution:

we have to evalute the given expresion

so,

[3^{-1} \times 4^{-1}+5^{-1}]^{-1​}

we know that,

x^{-1} =\frac{1}{x}

we will write the given expression

like

=[\frac{1}{3}\times\frac{1}{4}+\frac{1}{5} ]^{-1}

=[\frac{1}{3\times4}+ \frac{1}{5} ]^{-1}\\=[\frac{1}{12}+ \frac{1}{5} ]^{-1}\\\\=[\frac{5+12}{12\times 5} ]^{-1}\\\\=[\frac{17}{60}] ^-1

now inverse the fraction.

so we get

=\frac{60}{17}

Hence, the answer of [3^{-1} \times 4^1+5^{-1}]^{-1​} is =\frac{60}{17}

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