Question

Evaluate.(3^[-1]+4^1)x(7/12)^-1​

Answer 1

qᴜᴇꜱᴛɪᴏɴ

Evaluate.(3^[-1]+4^1)x(7/12)^-1

ᴀɴꜱᴡᴇʀ => 1

ꜱᴏʟᴜᴛɪᴏɴ ★ ★

ᴛᴏ ꜰɪɴᴅ ➡ ᴇᴠᴀʟᴜᴀᴛᴇ ᴛʜᴇ ꜰᴏʟʟᴏᴡɪɴɢ

ɢɪᴠᴇɴ:-

$( {3}^{ - 1} + {4}^{ - 1} ) { \binom{7}{12} }^{ - 1}$

ɴᴏᴡ , .

$( {3}^{ - 1} + {4}^{ - 1} ) { \binom{7}{12} }^{ - 1} = \binom{1 + 1}{3 + 4} \binom{7}{12} {}^{ - 1} \\ = > ( {3}^{ - 1} + {4}^{ - 1} ) \binom{7}{12} {}^{ - 1} = \binom{7}{12} \binom{7}{12} {}^{ - 1} = 1 \\ \\ hence \: ( {3}^{ - 1} + {4}^{ - 1} ) \binom{7}{12} {}^{ - 1} = 1$

Answer 2

Answer:

i can't understand what u mean