Math, asked by mannnatthanipckfj8, 1 year ago

Evaluate : √3÷1 sec 60° + cosec60°

Answers

Answered by sarkarsourendu1
1

=√3÷1×2+2/√3    (  sec60°=2 and cosec60°=2/√3)

=√3÷2+2/√3

=√3÷2√3+2/√3

=√3×√3/2(√3+1)

=3/2(√3+1)

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