Math, asked by samriddhimajumdar200, 9 months ago

Evaluate: 3㏒2- 1/3 ㏒27+ ㏒12- ㏒4 + 3㏒5

Answers

Answered by Anonymous
1

Answer:

3

Step-by-step explanation:

3log2-1/3(log27) + log12 - log4 + 3log5

log8 - log3 + log12 - log4 + log125

log8*12*125/3*4

log1000

3

Answered by earth2milkyway
1

Answer:

2.9997

Step-by-step explanation:

3log2-1/3log27+log12-log4+3log5

we know that mlogn=logn^m and 1/mlogn=logn^1/m

3log2-log27^(1/3)+log3×4-log4+3log5

3log2-log3+log3+log4-log4+3log5

3log2+3log5

3(log2+log5)

3(0.30102+0.69897)

3(0.99999)

2.99997

approximately 3

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