evaluate (3^2)^3+(2/3)^0 +(3)^5+(1/3)^4
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Answered by
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Step-by-step explanation:
(3^2)^3 + (2/3)^0 + (3)^5 + (1/3)^4
= (9)^3 + (2^0/3^0) + 243 + (1^4/3^4)
= 729 + (1/1) + 243 + (1/81)
= 729 + 1 + 243 + (1/81)
= 729 × 81 + 1×81 + 243 ×81 + 1/81
= 59,049 + 81 + 19,683 + 1 / 81
= 78,814 / 81
= 973.01 is the answer
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