Question

evaluate (3.29)^3 + (6.71)^3

Answer 1

a^3+b^3=(a+b)^3-3ab(a+b)
=(3.29+6.71)^3-3*3.29*6.71(10)
=1000-662.277
=337.723

Answer 2

( 3.29)³ + (6.71)³

use formula,
a³ + b³ = (a + b)( a² + b² -ab )

so,
(3.29)³ + (6.71)³

=(3.29 + 6.71){ ( 3.29)² + (6.71)² -(3.29)(6.71)}

= 10 {( 3.29 + 6.71)² -2(3.29)(6.71)-(3.29)(6.71)}

= 10 { 100 -3(3.29)(6.71)}
= 10× (100-66.2277)
=10× 33.773
=337.73