Math, asked by Legend3678, 4 months ago

evaluate: |(3-2i)/(3+2i) + (3+2i)/(3-2i)|​

Answers

Answered by pulakmath007
4

SOLUTION

TO EVALUATE

\displaystyle\sf{  \bigg| \:   \frac{3 - 2i}{3 + 2i}  + \frac{3  +  2i}{3  -  2i}    \: \bigg| }

EVALUATION

Here the given expression is

\displaystyle\sf{  \bigg| \:   \frac{3 - 2i}{3 + 2i}  + \frac{3  +  2i}{3  -  2i}    \: \bigg| }

We simplify it as below

\displaystyle\sf{  \bigg| \:   \frac{3 - 2i}{3 + 2i}  + \frac{3  +  2i}{3  -  2i}    \: \bigg| }

\displaystyle\sf{   = \bigg| \:   \frac{{(3 - 2i)}^{2}  + {(3  + 2i)}^{2} }{(3 + 2i)(3 - 2i)}     \: \bigg| }

\displaystyle\sf{   = \bigg| \:   \frac{2{ \big[(3 )}^{2}  + {(2i)}^{2} \big]}{( {3}^{2}  ) -  {(2i)}^{2} }    \: \bigg| }

\displaystyle\sf{   = \bigg| \:   \frac{2\big[ 9 + 4{i}^{2} \big]}{9 - 4 {i}^{2} }    \: \bigg| }

\displaystyle\sf{   = \bigg| \:   \frac{2\big[ 9  - 4 \big]}{9  + 4 }    \: \bigg| }

\displaystyle\sf{   = \bigg| \:   \frac{10}{13}    \: \bigg| }

\displaystyle\sf{   = \:   \frac{10}{13}    \: }

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