Question

evaluate {(⅓)-³–(½)-³}÷(¼)-³​

Answer 1

Answer:

[(1/3)-²-(1/2)-³]÷[(1/4)]-²

[(1/3)-²-(1/2)-³]÷[(1/4)]-²

[(3/1)²-(2/1)³]÷[(4/1)]²

$(9 - 8) \div \frac{1}{16}$

$1 \times 16$

$16$

Answer 2

Step-by-step explanation:

(1/3)-3-(1/2)-³]÷[(1/4)]-²

[(1/3)-3-(1/2)-³]÷[(1/4)]-²

[(3/1)3-(2/1)³]÷[(4/1)]²

(9 - 8) \div \frac{1}{16}(9−8)÷161

1 \times 161×16

1616