Math, asked by iforgotmyemail121, 4 days ago

evaluate 3.6x + 4.5y when x = 3 and y = 7

Answers

Answered by bhuvanasrigk06
0

Answer:

3.6(3)+4.5(7)

10.8+31.5

42.3

Answered by sakshii8080
0

Answer:

Therefore after evaluation we get the value as 42.3

Step-by-step explanation:

According to the information provided in the question.

It is stated in the preceding question that,

The presented information is equation 3.6x + 4.5y,

X = 3 and y = 7,

We need to evaluate the given equation.

Here we have to use the substitution method.

The equation is 3.6x+4.5y

substitute the value of x=3 and y =7 we get,

3.6(3)+4.5(7)\\

When 3.6 is multiply by 3 we get 10.8 and 4.5 multiply by 7 we get 31.5

Thus the equation will be,

10.8+31.5\\(10+31)+(0.8+0.5)\\(41)+(1.3)\\42.3

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