Math, asked by rinisen, 8 months ago

Evaluate (3.6x^6y^3)*(2.1x^2y^2) when x=1 and y =0.5
plz solve with steps friends

Answers

Answered by christapher22
0

Answer:Method 1

2

x

6

=

12

2

x

6

+

6

=

12

+

6

add 6 to each side

2

x

=

18

2

x

2

=

18

2

divide each side by 2

x

=

9

Method 2

2

x

6

=

12

2

x

6

2

=

12

2

divide each side by 2

2

x

2

6

2

=

12

2

separate the fractions

x

3

=

6

simplify

x

3

+

3

=

6

+

3

add 3 to each side

x

=

9

Step-by-step explanation:

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