Question

Evaluate 3+jk+k^3 when j=2 and k=6.

Answer 1

3+jk+k^6
j=2 & k=6

substituting the values, we have
= 3+2(6)+6^3
= 3+12+216
= 231

Ans=231

Answer 2

Answer:

value of 3+jk+k³ = 231

Step-by-step explanation:

If j=2 and k = 6 ,then

the value of 3+jk+k³

= 3+2×6+6³

= 3+12+216

= 231

Therefore,

value of 3+jk+k³ = 231

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