Math, asked by aswanthsukumar4354, 1 year ago

Evaluate : 307*293
:4.15*3.85

Answers

Answered by BrainlyKing5
12

\bold{Hey\: Mate \:Here \:Is\: Your\: Answer...}



Q 1 ) Evaluate 307 × 293


\large{\underline{\bold{{Solution...}}}


Now According To Question We Need To Evaluate 307 × 293


So Now We Can Write


\bold{307 \:As \:300\: + \:7}


Similarly


We Can Write


\bold{293\: As \:300 \:- \:7}


So Now Using This Form Instead Of 307 × 293 We Have


\boxed{\bold{(300 + 7) (300 - 7 )}}


Therefore Now We Know An Identity That Is ...


\boxed{\bold{( a + b ) ( a - b ) = {a}^{2}\:-\: {b}^{2} \:}}


Here


\bold{\: a\: = \:300\: \;And \;\: b\: =\: 7 }


So We Have ...


\bold{(300 + 7)(300 - 7) = {300}^{2} - {7}^{2}}


That Is ...


\bold{307 \times 293 = 90000 - 49}


That Is ...


\bold{300 \times 293 = 89951}


\bold{So \:We\: Have \:Answer \:For \:Question\: 1\: Equal\: To\: ...}


\boxed{\bold{89951}}


Now Let's Move To Second Question ..



Q 2 ) Evaluate 4.15 × 3.85


So Now In This Question We Can Use Same Logic That Is ....


We Can Write


\bold{4.15 \;\:As\;\; 4.00 \:+ \:0.15}


And


\bold{3.85 \:\:As \:\;4.00 - 0.15 }


So Now Putting This Form Of Numbers In Question We Have ....


\bold{(4.00\: + \:0.15)(4.00-0.15 )}


Now By Using The Same Identity That We Used Above Where


\bold{a\: =\: 4 \:And\:b\: =\: 0.15}


We Have ...


\bold{(4.00\: +\:0.15)(4.00 \:- \:0.15)\:=\: {4.00}^{2} - {0.15}^{2} }


That Is ..


\bold{4.15 \times 3.85 = 16 - \: 0.0225}


That Is ..


\bold{4.15 + \times 3.85 = 15.9775}


Therefore Answer For Second Question Is ...


\boxed{\bold{15.9775}}


Hence The Required Answers Are


\boxed{\bold{89951\: \;And\:\;15.9775}}


\large{\bold{Thanks..}}

Similar questions