Question

Evaluate √37 correct up to three decimal places.​

Answer 1

Answer:

$\sqrt{37} = {(36 + 1)}^{ \frac{1}{2} }$

$= {(36)}^{ \frac{1}{2} } {(1 + \frac{1}{36}) }^{ \frac{1}{2} }$

$= 5 {(1 + 0.028)}^{ \frac{1}{2} }$

$= > 5(1 + \frac{1}{2} (0.028) + \frac{ \frac{1}{2}( - \frac{1}{2}) }{2} {(0.028)}^{2} ....)$

we have neglected thw terms containing power of 0.028.

√37 = 6(1+0.014)

=> 6[1+0.014]= 6[1.014]

=> 6.084

Answer 2

Explanation:

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